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Deep Nerd Topic: is 0.999999999999999999999999999 (repeating) =1


E.V.I.L.

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Well, what's your opinion on this. Personally, I think it does.

Why?

0.3333333333333333333333333333333 is 1/3

0.6666666666666666666666666666666 is 2/3

0.9999999999999999999999999999999 would be 3/3, along with 1, right?

It's also been proven algebraically.

0.9999... = 1

Thus x = 0.9999...

10x = 9.9999...

10x - x = 9.9999... - 0.9999...

9x = 9

x = 1.

Also, in a repeating, 9 NEVER ends, so it's very possible it equals one and we haven't dug down enough in the number to see that.

Even if it doesn't equal 1 though, it is definitely a very very very very very very close number to 1.

What do you guys think. I think it's an interesting topic, but yet again I'm a nerd.

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I'm pretty darn sure you're right. But here's my wacky take on it:

I think it doesn't =1. I think it just means that the 9 repeats and goes on and on and on but it's just so infinite and minute that it's just really close to hitting 1. Same thing goes for when you graph hyperbolas with asymptotes (don't know if you've ever learned those yet). The hyperbola itself is super close to hitting the asymptote line, but it is infinite and goes on forever and the asymptote never touches the line. But that's just my theory. Laugh and scoff if you want to. Also, I know how you got the 10x, but:

10x = 9.9999...

10x - x = 9.9999... - 0.9999...

Why did you just subtract the random x from the 10x? Wouldn't that mean you would have to subtract an x to the other side of the equation too? But you can't cuz there isn't another variable on the other side and.......... ah forget it.

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I'm pretty darn sure you're right. But here's my wacky take on it:

I think it doesn't =1. I think it just means that the 9 repeats and goes on and on and on but it's just so infinite and minute that it's just really close to hitting 1. Same thing goes for when you graph hyperbolas with asymptotes (don't know if you've ever learned those yet). The hyperbola itself is super close to hitting the asymptote line, but it is infinite and goes on forever and the asymptote never touches the line. But that's just my theory. Laugh and scoff if you want to. Also, I know how you got the 10x, but:

Why did you just subtract the random x from the 10x? Wouldn't that mean you would have to subtract an x to the other side of the equation too? But you can't cuz there isn't another variable on the other side and.......... ah forget it.

10x-x=9x

9.999999999999999999999=10x

0.999999999999999999999=x

Therefore

10x-x=9.999999999999999999-0.999999999999999999

and the parabola thing I agree with it,

but if 0.33333333333333333 is 1/3

0.66666666666666666666666 is 2/3

and 1 is 3/3

what is 0.99999999999999999?

If anything, it makes no sense for 1 to be 3/3.

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I don't believe that 1=0.9999999

If you believe, I wonder if you don't believe that 2+2=5. :huh:

:workout:

2+2 does not equal 5 though

:P

Now I'm open to 0.9999999999999999999999999999999 getting closer and closer to 1 and never reaching it. But as of current, it's like 1. Infinite numbers to us aren't really too discovered yet. It's like how negative numbers were just a stupid concept back in the B.C days.

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2+2 does not equal 5 though

:P

Now I'm open to 0.9999999999999999999999999999999 getting closer and closer to 1 and never reaching it. But as of current, it's like 1. Infinite numbers to us aren't really too discovered yet. It's like how negative numbers were just a stupid concept back in the B.C days.

I agree with this.

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